The splat operator is confusing and here is why…
It does 2 things that are the exact opposite of each other.
Let me explain…
It destructures an array, which looks something like this:
But it can also be used to construct an array:
If you think about this, it is doing two very different things.
One takes an array and removes the surrounding .
The other takes a value and adds the surrounding .
The only question we need to answer then is when does it destruct and when does it construct? 🤔
If you use it when defining a method it will take any argument you give it and construct it into an array.
If you use it when passing arguments as an array to a method it will deconstruct the array into arguments.
Hopefully now we can understand code that looks like this:
As an aside, the reason for the above class method of
perform, is so you can easily call
Thing.perform(), without having to first instantiate the object.
*args means that if our expected parameters in the
initialize method were to change
we would never have to change them in the
perform class method.
Credit to this article which helped to shape my understanding.